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第 14 题答案应为 red #3

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fighterleslie opened this issue May 25, 2015 · 0 comments
Open

第 14 题答案应为 red #3

fighterleslie opened this issue May 25, 2015 · 0 comments

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@fighterleslie
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#awesome .favorite:not(#awesome) .highlight 的特异性为 0, 2, 2, 0
#awesome .highlight:nth-of-type(1):nth-last-of-type(1) 的特异性为 0, 1, 3, 0

注意：:not(X) 伪类选择器的特异性为其参数 X 的特异性，:not 伪类选择器本身不增加选择器的特异性。
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@fighterleslie