Allow APIRouter to be made from create_service

[slamer59]

There is no problem to use APIRouter instead of FastAPI.
Exemple :

app = FastAPI()
router = APIRouter()

@app.get("/")
def read_main():
return {"message": "Hello World from main app"}

router: APIRouter = create_service(router,
"api.ex1:chain",
)
app.include_router(router)

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Name	Status	Preview	Comments	Updated (UTC)
langcorn	✅ Ready (Inspect)	Visit Preview	💬 Add feedback	Aug 24, 2023 3:18pm

[msoedov]

I have not tested it yet but it should be possible to use mount

app = FastAPI()
router = APIRouter()


@app.get("/")
def read_main():
    return {"message": "Hello World from main app"}


lang_app: FastAPI = create_service(
    "api.ex1:chain",
)

app.mount("/subapi", lang_app)

[slamer59]

Hello.
Yes you are right on this.

But in my use case cannot define FastAPI application.

[msoedov]

Would your use case work with lang_app.router?

[msoedov]

Did it solve your issue?

[slamer59]

I am not able to have access to app for my use case.
So the only solution is to do my proposal.

[msoedov]

Hi @slamer59, thx for your patch and contribution! Let me test it locally and get back to you.